Chapter 5. Listing files in your bucket

Procedure

1. In the Jupyter notebook, locate the following code for listing files.

   #List files
   #Replace <bucket_name> with the name of the bucket.
   bucket_name = ‘<bucket_name>’
   s3_client.list_objects_v2(Bucket=bucket_name)

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2. Replace <bucket_name> with the name of your own bucket, as shown in the example, and then run the code cell.

   #List files
   #Replace <bucket_name> with the name of the bucket.
   bucket_name = ‘aqs27-registry’
   s3_client.list_objects_v2(Bucket=bucket_name)

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   The output displays information about the files that are available in the specified bucket.

3. Locate the code cell that lists only the names of the files.

   #Print only names of files
   bucket_name = ‘<bucket_name>’
   for key in s3_client.list_objects_v2(Bucket=bucket_name)[‘Contents’]:
   	print(key[‘Key’])

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4. Replace <bucket_name> with the name of your bucket, as shown in the example, and run the code cell:

   #Print only names of files
   bucket_name = ‘aqs27-registry’
   for key in s3_client.list_objects_v2(Bucket=bucket_name)[‘Contents’]:
   print(key[‘Key’])

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   The output displays a list of file names that are available in the specified bucket.

5. Refine the previous query to specify a file path, by locating the following code cell:

   bucket_name = ‘<bucket_name>’
   for key in s3_client.list_objects_v2(Bucket=bucket_name,Prefix=’<start_of_file_path’)[‘Contents’]:
   print(key[‘Key’])

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6. Replace <bucket_name> and <start_of_file_path> with your own values and run the code cell.